| LOST-Chall http://lost-chall.wechall.net/forum/ |
|
| S01 E16 "Outlaws" http://lost-chall.wechall.net/forum/viewtopic.php?f=2&t=16 |
Page 1 of 2 Next » |
| Author: | PeterSeb [ Tue Apr 15, 2008 9:59 am ] |
| Post subject: | S01 E16 "Outlaws" |
Hey guys, i've got a problem with solving this chall... could anybody give me a hint?! Do i have to put in a number (like "28") or do i have to write it out (like "Fiftysix") I've tried both variants, but i didn't got it so far... 
so far... PeterSeb |
|
| Author: | PeterSeb [ Tue Apr 15, 2008 10:07 am ] |
| Post subject: | Re: S01 E16 "Outlaws" |
I'm sorry, I forgot to login to the forum.. -.- so this is my post... ^^ |
|
| Author: | xmadx [ Tue Apr 15, 2008 12:33 pm ] |
| Post subject: | |
Just did this one - it accepts the solution in digits just fine (e.g. "28") xmadx |
|
| Author: | Guest [ Sat Apr 19, 2008 5:15 pm ] |
| Post subject: | |
Is XXXXXY == YXXXXX (5X1Y) or does it count twice? |
|
| Author: | Bregi [ Sat Apr 19, 2008 10:07 pm ] |
| Post subject: | |
That's the same. Imagine you would put it together and you wouldn't see the begining and the end. Greez |
|
| Author: | quangntenemy [ Sun Apr 20, 2008 8:26 am ] |
| Post subject: | |
How about XYZXYZ and YZXYZX? |
|
| Author: | Bregi [ Sun Apr 20, 2008 8:57 am ] |
| Post subject: | |
Yes, that's the same too, quangntenemy. |
|
| Author: | xmadx [ Mon Apr 21, 2008 4:16 pm ] |
| Post subject: | |
Thinking of it as a neckchain / necklace with different coloured beads on it might help. The problem wants distinct values without flipping or rotating the chain. |
|
| Author: | smutley [ Fri May 16, 2008 2:53 pm ] |
| Post subject: | |
Can I confirm that XXXXXX is different to YYYYYY? This should be easy, but for some reason I am missing something 
|
|
| Author: | Bregi [ Fri May 16, 2008 3:03 pm ] |
| Post subject: | |
Yes this is diffrent. XXXXXXX YYYYYY ZZZZZZ are 3 possibilities you can do with 1 color. Hope that helped
|
|
| Author: | krueger [ Sun May 25, 2008 6:08 pm ] |
| Post subject: | |
And you are sure the solution you are expecting is the right one?
I am pretty sure the value i am entering is correct, but it doesn't get accepted. |
|
| Author: | Bregi [ Sun May 25, 2008 7:11 pm ] |
| Post subject: | |
As there are 31 people who solved it I'm sure, yes =) You can PM me your solution and I can tell you if you're near. Greez |
|
| Author: | reesylou [ Tue Apr 28, 2009 8:59 am ] |
| Post subject: | |
Ok, I thought I had the right answer, but it seems I was mistaken. I know XYXZXY is the same as YXZXYX, but is XYXZXY the same as XXXYYZ. If so, the answer I have should be right. |
|
| Author: | sabretooth [ Tue Apr 28, 2009 10:01 am ] |
| Post subject: | |
No the 2nd one is not the same. This is because the beads are in a different order. Example XYZZYX == ZZYXXY imagine this as a loop, the end continues to the beginning we still have 2 X 1 Y 2 Z and 1 Y in that order.... just starting in a different place Start on the bold letter then read til the end looping if necessary til all letters are used: XYZZYX == ZZYXXY in your 2nd example we have XYXZXY and XXXYYZ these are different because if they were looped then the first wouldnt equal the 2nd no matter where in the loop you started 
hope that helps sabre |
|
| Author: | reesylou [ Wed Apr 29, 2009 12:05 am ] |
| Post subject: | |
OK. That is the way I hoped and feared it was. Hoped because it meant I understood it correctly, feared because I'm not sure how to calculate it that way.  Back to the drawing board.
|
|
| Page 1 of 2 | All times are UTC |
|
Powered by phpBB® Forum Software © phpBB Group
http://www.phpbb.com/ |
|