Great one!!!!
i have take an hour or two.. because i'm lazy as a bear and was too tired to code...
so i have taken pen and paper and do the dirty work at hand...
GOOD one!! thx a lot Criple_ripper
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| S3PR#Nearest Neighbour http://lost-chall.wechall.net/forum/viewtopic.php?f=13&t=151 |
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| Author: | Nuke [ Mon Jun 16, 2008 9:59 pm ] |
| Post subject: | S3PR#Nearest Neighbour |
Great one!!!!
i have take an hour or two.. because i'm lazy as a bear and was too tired to code...
so i have taken pen and paper and do the dirty work at hand... GOOD one!! thx a lot Criple_ripper
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| Author: | criple_ripper [ Mon Jun 16, 2008 10:54 pm ] |
| Post subject: | |
i'm glad you like it Nuke...thought a programming chall would be good...yes you can do it with pen and paper but it's easier to write a program and do it for you in 2 seconds...anyone who knows what it's about will write a program in 15 minutes... |
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| Author: | Nuke [ Tue Jun 17, 2008 7:46 am ] |
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I agreed, the coding a program is a better way to solve the challenge. but as i said yesterday was reaaaallyyyy lazy... or i have just time to waste 
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| Author: | paipai [ Tue Jun 17, 2008 4:02 pm ] |
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could anyone explain what must to do here, i dont understand what is "to find out the best route visiting all the vertices/cities to ship the boxes." thx 
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| Author: | criple_ripper [ Tue Jun 17, 2008 4:42 pm ] |
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hi paipai...you could start by viewing the source of the page and google one name you 'll find there then you'll know what to do...
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| Author: | Nuke [ Tue Jun 17, 2008 8:02 pm ] |
| Post subject: | |
another starting point is the name of the challenge, that help a lot
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| Author: | Alice [ Sat Jun 21, 2008 9:33 pm ] |
| Post subject: | |
I was a good little programmer and wrote a program to do this. The shortest path I get has length 144 (I hope this number is not much of a spoiler). In fact, I got 4 paths of that length -- two of them are a reversal of the other two -- but none of them work as the answer. Is there an even shorter path that my program somehow missed? |
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| Author: | criple_ripper [ Sat Jun 21, 2008 9:44 pm ] |
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hi alice...i think you missed something with your program...the right length is bigger and you get 2 possible of these CIRCLES with the same length...what programming language did you used?if you want send me your code and i'll take a look at it... EDIT just changed the weight of one edge...just to make the matrix symetrical... but it has nothing to do with the solution:) |
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| Author: | Alice [ Mon Jun 23, 2008 3:31 pm ] |
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I've redone it as a circle, but still didn't get the right answer, because the shortest path my program found is actually 7 shorter than the intended path. I will msg you with with more details. |
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| Author: | criple_ripper [ Mon Jun 23, 2008 5:51 pm ] |
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congrats Alice!!I sent you a pm to talk about it a bit more...for those who still don't know what to do...wikipedia can always help... |
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| Author: | vasis [ Fri Mar 16, 2012 10:49 pm ] |
| Post subject: | Re: S3PR#Nearest Neighbour |
What should the solution look like? Is it something like "5O7LI0PNU...", or I should add hyphens/commas/god knows what? And can i assume that "7" is the start and the end? |
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| Author: | Bregi [ Sun Mar 18, 2012 6:34 pm ] |
| Post subject: | Re: S3PR#Nearest Neighbour |
Yes vasis, but it's not that big what you will have to enter, and it makes sense Bregi |
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| Author: | thefinder [ Fri Dec 15, 2017 6:23 pm ] |
| Post subject: | Re: S3PR#Nearest Neighbour |
Hi, as there are some errors on this chall I add a comment: At the end we come back to the starting point. And also, switch 'I' and 'O' on the matrix file.=> It has been fixed! |
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